Ranking brightness of lightbulbs in a circuit

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Homework Help Overview

The discussion revolves around a circuit involving light bulbs, specifically addressing the brightness ranking of bulbs A, B, and C. The original poster seeks to understand why bulb A is the brightest while bulbs B and C are equally bright but dimmer than A.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between voltage drops across the bulbs and their brightness. The original poster suggests that the power is less for bulbs B and C due to a greater voltage drop across them. Others clarify the configuration of the circuit, indicating that bulbs A, B, and C are arranged in a way that affects their voltage and power distribution.

Discussion Status

The discussion is active, with participants providing clarifications regarding the voltage drop across the bulbs and how it relates to their brightness. Some participants have offered insights into the parallel configuration of the bulbs, suggesting that this impacts the power calculations for each bulb.

Contextual Notes

There is a focus on understanding the implications of the circuit's configuration, particularly regarding the assumptions about voltage drops and power in parallel circuits. The original poster's understanding of the relationship between current, voltage, and brightness is being examined.

ikihi
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Homework Statement



In the circuit shown, all the light bulbs are the same. Why is the following statement true? :

A is the brightest. B and C are equally bright, but are dimmer than A.


https://pbs.twimg.com/media/C6GllsQVMAA4chz.jpg:large
https://twitter.com/FauxNews101/status/838133087464640513

Homework Equations



P = I * V

The Attempt at a Solution


[/B]
There is more of a voltage drop across B to C than A, so the power is less for both B and C than A since power is proportional to I and V? Since B and C are the same then they should be the same brightness because they each have the same resistance, in series?
 
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ikihi said:
There is more of a voltage drop across B to C than A,
No. lightbulb A is in parallel with B+C. So the voltage drop across B is half of that across A, and the drop across C is half that across A.

Try again? :smile:
 
berkeman said:
No. lightbulb A is in parallel with B+C. So the voltage drop across B is half of that across A, and the drop across C is half that across A.

Try again? :smile:

The voltage drop of B+C equals the voltage drop of A. This is so because light bulb A equals the voltage drop across the equivalent of B+C since light bulbs in parallel have the same voltage. So B or C has half the voltage that A does; and because of that, the power for B and C is equal, but B or C is less power than A.
 
ikihi said:
The voltage drop of B+C equals the voltage drop of A. This is so because light bulb A equals the voltage drop across the equivalent of B+C since light bulbs in parallel have the same voltage. So B or C has half the voltage that A does; and because of that, the power for B and C is equal, but B or C is less power than A.
Yes, good. :smile:
 
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