Ranking brightness of lightbulbs in a circuit

In summary, the statement that A is the brightest, while B and C are equally bright but dimmer than A, is true because light bulb A has a greater voltage drop than B and C, which are in parallel and therefore have equal voltage drops. This results in B and C having half the voltage and power of A.
  • #1
ikihi
81
2

Homework Statement



In the circuit shown, all the light bulbs are the same. Why is the following statement true? :

A is the brightest. B and C are equally bright, but are dimmer than A.


https://pbs.twimg.com/media/C6GllsQVMAA4chz.jpg:large
https://twitter.com/FauxNews101/status/838133087464640513

Homework Equations



P = I * V

The Attempt at a Solution


[/B]
There is more of a voltage drop across B to C than A, so the power is less for both B and C than A since power is proportional to I and V? Since B and C are the same then they should be the same brightness because they each have the same resistance, in series?
 
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  • #2
ikihi said:
There is more of a voltage drop across B to C than A,
No. lightbulb A is in parallel with B+C. So the voltage drop across B is half of that across A, and the drop across C is half that across A.

Try again? :smile:
 
  • #3
berkeman said:
No. lightbulb A is in parallel with B+C. So the voltage drop across B is half of that across A, and the drop across C is half that across A.

Try again? :smile:

The voltage drop of B+C equals the voltage drop of A. This is so because light bulb A equals the voltage drop across the equivalent of B+C since light bulbs in parallel have the same voltage. So B or C has half the voltage that A does; and because of that, the power for B and C is equal, but B or C is less power than A.
 
  • #4
ikihi said:
The voltage drop of B+C equals the voltage drop of A. This is so because light bulb A equals the voltage drop across the equivalent of B+C since light bulbs in parallel have the same voltage. So B or C has half the voltage that A does; and because of that, the power for B and C is equal, but B or C is less power than A.
Yes, good. :smile:
 
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