Identifying forces (normal force, weight, gravity)

Click For Summary
SUMMARY

The discussion centers on the identification and distinction between normal force and weight (gravity) acting on an object at rest on a surface. It clarifies that the normal force, exerted by the ground, and the weight, due to gravity, are equal and opposite forces that act on the object. The conversation emphasizes the importance of free body diagrams (FBD) in illustrating these forces, noting that while the normal force and weight are equal when the object is at rest, they do not represent Newton's third law pairs. Instead, the action-reaction pairs involve the contact force exerted by the object on the ground and the gravitational force the object exerts on the Earth.

PREREQUISITES
  • Understanding of Newton's laws of motion, particularly Newton's third law.
  • Familiarity with free body diagrams (FBD) and their construction.
  • Basic knowledge of forces, specifically normal force and gravitational force.
  • Concept of action-reaction force pairs in physics.
NEXT STEPS
  • Study the construction and interpretation of free body diagrams (FBD).
  • Explore Newton's laws of motion in greater detail, focusing on action-reaction pairs.
  • Investigate the concept of contact forces and their implications in physics.
  • Examine examples of normal force and weight in various physical scenarios.
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone seeking to deepen their understanding of forces acting on objects in static equilibrium.

KingAlexander211B
Messages
4
Reaction score
0
image.png

When an object is resting on a surface such as the floor, there are exerted on it two forces: The normal force - force of the ground - and the weight (the force of gravity, the Earth pushing the object down), the forces drawn on the left.

What are the forces on the right? Are they the same as the ones on the left or are they something else?

Isn't the repulsion by the ground the same as the force of the ground?
 

Attachments

  • image.png
    image.png
    10.5 KB · Views: 1,014
Last edited by a moderator:
Physics news on Phys.org
You are mixing up two concepts, the free body diagram and the force pairs from Newton’s third law.

The free body diagram has to do with what forces act on a body of your choice. If you draw a FBD you should only draw the forces that act on the object. If you here take the ”object”, the forces in the FBD would be gravity and the normal force. If the object is at rest they are going to be equal and opposite - but they are not a Newton 3 pair.

The N3 pair of the normal force is the contact repulsion force from the object on the ground and the N3 pair of the gravitational force on the object is the gravitational force that the object excerts on the Earth.
 
  • Like
Likes   Reactions: Chestermiller
KingAlexander211B said:
View attachment 239644
Isn't the repulsion by the ground the same as the force of the ground?
Yes. Not a very good diagram. Redundant and not clear on which object the forces act.
 

Similar threads

  • · Replies 51 ·
2
Replies
51
Views
5K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 49 ·
2
Replies
49
Views
4K
  • · Replies 10 ·
Replies
10
Views
771
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 10 ·
Replies
10
Views
893
  • · Replies 20 ·
Replies
20
Views
4K