Identifying Preferred Reactivity in Organic Compounds

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SUMMARY

The discussion focuses on identifying the preferred reactivity of functional groups in organic compounds, specifically an ether and an alcohol. It concludes that in the presence of excess HI, the ether reacts preferentially due to steric factors and the preservation of aromaticity, while the alcohol does not react. The reasoning provided emphasizes the importance of molecular structure over merely identifying functional groups, highlighting that the ether's oxygen is less sterically hindered compared to the alcohol's oxygen. This understanding is crucial for predicting reaction outcomes in organic chemistry.

PREREQUISITES
  • Understanding of functional groups in organic chemistry
  • Knowledge of steric hindrance and its effects on reactivity
  • Familiarity with aromaticity and resonance in organic compounds
  • Experience with reactions involving hydrogen iodide (HI)
NEXT STEPS
  • Study the mechanisms of reactions involving ethers and alcohols
  • Learn about steric effects in organic reactions
  • Research the concept of aromaticity and its implications in chemical reactivity
  • Explore the reactivity of various functional groups under different conditions
USEFUL FOR

Chemistry students, organic chemists, and researchers interested in reaction mechanisms and the behavior of functional groups in organic compounds.

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In organic if you have more than one functional group.. how do you know which will react in preference?

In the attachment I've got an organic compound which has an ether and alcohol.

In terms of naming the alcohol gets preference.

It reacts with excess HI and the alcohol apparently doesn't react.. chemical changes occur with the ether..
 

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my first reaction was that it should react with the alcohol... but if your text or teacher says it doesn't then...

my guess is that instead of looking at "functional groups" per se, try to understand the structure of the molecule. Both oxygens have free electrons but the ether O is farther out from the phenyl ring = less sterically hindered. So then the acid would protonate the ether O instead of the alcohol O. Then again, I could be completely wrong, but that's what makes sense.
 
Oh yeah, it won't react with the alcohol because if you protonate the alcohol O, you lose aromaticity in resonance. Since aromaticity is a strong driving force, the reaction with the alcohol O is not favored. Does that make sense?
 

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