Identifying Vertical Asymptotes: A Non-Factoring Method

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Discussion Overview

The discussion revolves around identifying vertical asymptotes of a rational function, particularly focusing on methods that do not involve factoring the denominator. Participants explore various approaches to solve for vertical asymptotes, including attempts at factorization and the implications of their findings.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant expresses difficulty in identifying vertical asymptotes due to a complex denominator and questions the necessity of factoring.
  • Another participant suggests that factoring is essential and proposes a substitution method to simplify the factorization process.
  • Several participants share their factorization attempts for both the numerator and denominator, with varying degrees of success.
  • There is a correction offered regarding the factorization of the numerator, indicating that some participants may have made errors in their calculations.
  • Participants discuss the cancellation of common factors and its effect on the resulting expression.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the necessity of factoring for identifying vertical asymptotes, with some advocating for it while others seek alternative methods. The discussion remains unresolved regarding the best approach to take.

Contextual Notes

Some participants' factorization attempts may depend on specific assumptions about the expressions involved, and there are indications of unresolved mathematical steps in their discussions.

Teh
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im stuck on identifying vertical asymptotes because of this nasty denominator. My professor telling me to factor it out but, is there different way to solve for the vertical asymptotes.
 

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the said:
im stuck on identifying vertical asymptotes because of this nasty denominator. My professor telling me to factor it out but, is there different way to solve for the vertical asymptotes.
Other than graphing, not that I know of.

You need to factor [math]x^4 - 61x^2 + 900[/math]. If you set [math]y = x^2[/math] then you have to factor [math]y^2 - 61y + 900[/math]. Are you able to do that?

-Dan
 
i did! for the denominator it is (x+5) (x+6) (x-5) (x-6) for the top i am not sure
 
the said:
i did! for the denominator it is (x+5) (x+6) (x-5) (x-6) for the top i am not sure

Surely you can at least see some common factors...
 
yes also did tried it this is what i got 2x^2 (x^2 + x - 30) is equal to 2x^2 (x-6) (x+5)... then cancel it out with (x-6) (x+5)
 
Your factorization of the numerator is close, but not quite correct...check your signs. :D
 
ahhh okay (x+6) and (x-5) canceling with (x+6) (x-5) leaving 2x^2 / (x-6) (x+5)
 

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