Identities between exponential and logarithmic functions?

1. Jul 13, 2011

romsofia

Hello! I was wondering if they're any identities between exponential and logarithmic functions? Maybe identities isn't the right word, but what I'm talking about is something like euler's formula. Other than than $${e^x}$$ and $${ln(x)}$$ are inverses, if that counts.

Any help is very much appreciative!

Last edited: Jul 13, 2011
2. Jul 14, 2011

JJacquelin

Let f=exp(x) and g=ln(x)
Of course there are basic relationships :
x = ln(f) = exp(g)
ln(exp(x)) = exp(ln(x))

3. Jul 14, 2011

romsofia

AKA inverses, as I said other than that. Thanks for the help though.

4. Jul 14, 2011

micromass

Well, since these inverses are the definition of the logarithm, it follows that any other identity can be derived from those. So I'm not sure what kind of identities you want?? It would help us if you told us what you are looking for and why...

5. Jul 14, 2011

romsofia

I'm looking for a way to substitute $${1/ln(x)}$$ with an exponential function to help solve an integral (the integral, i've asked about it here before, is $$\int sin(x)/ln(x)\,dx$$ sorry, don't know how to do fractions within integrals in latex!). Only substitution I can think of is $${1/ln(x)=\log_x e}$$. However, that won't help since it's still a logarithmic function!

6. Jul 14, 2011

micromass

The integral (right click to see how I did the fraction)

$$\int{\frac{\sin(x)}{ln(x)}dx}$$

is not solvable using elementary functions, so you won't be able to solve it. The best thing to do is to find a series solution, which is also not easy.

7. Jul 14, 2011

romsofia

Thanks for showing on how to do fractions in integrals
Well, I was thinking if we were to go to the complex plane for the problem, then maybe we could solve it? Since we can make the substitution $${sin(x)=1/2i(e^{-ix}-e^{ix})}$$ However, I haven't had much exposure to complex numbers so I'm not really sure if it would make a difference if we were to work in the complex plane! However, I'm still lost on any exponential functions that we would be able to substitute for $${1/ln(x)}$$

8. Jul 14, 2011

micromass

Going to the complex numbers wouldn't make any difference. Mathematica uses an algorithm that decides 100% if there is a solution, and if it says that there isn't, then there isn't (even when working with complex numbers).

9. Jul 14, 2011

romsofia

Ahhh, okay thanks for all the help once again micromass :D!