*If (dy)/dx= x^2 y^2, then (d^2 y)/(dx^2 )=

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The discussion centers on the differential equation $\frac{dy}{dx} = x^2 y^2$ and the subsequent calculation of the second derivative $\frac{d^2 y}{dx^2}$. The user applies the product rule to derive the expression $\frac{d^2 y}{dx^2} = x^4 2y^3 + 2xy^2$. The calculations are confirmed as accurate, indicating a solid understanding of differentiation techniques in calculus.

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karush
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If $\displaystyle\frac{dy}{dx}= x^2y^2$, then $\displaystyle\frac{d^2 y}{dx^2} =$

using the product rule

$\displaystyle x^22y (x^2y^2)+ 2xy^2$

$\displaystyle x^42y^3+2xy^2$

don't think this is the answer??
 
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Looks good to me. (Nod)
 

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