MHB *If (dy)/dx= x^2 y^2, then (d^2 y)/(dx^2 )=

[karush]

If $\displaystyle\frac{dy}{dx}= x^2y^2$, then $\displaystyle\frac{d^2 y}{dx^2} =$

using the product rule

$\displaystyle x^22y (x^2y^2)+ 2xy^2$

$\displaystyle x^42y^3+2xy^2$

don't think this is the answer??

 

[MarkFL]

Looks good to me. (Nod)