If f is differentiable at x = a, evaluate lim[h->0] (f(a+2h)-f(a+3h))/h

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SUMMARY

The limit evaluation of lim[h->0] (f(a+2h)-f(a+3h))/h, given that f is differentiable at x = a, results in -f'(a). The solution involves applying the definition of the derivative, f'(a) = lim[h->0] (f(a+h)-f(a))/h, and manipulating the limit expression to isolate terms involving f'(a). The final expression confirms that the limit simplifies to -f'(a) through the use of algebraic manipulation and properties of limits.

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Homework Statement



If f is differentiable at x = a, evaluate lim[h->0] (f(a+2h)-f(a+3h))/h


Homework Equations



We know that f'(a) = lim[h->0] (f(a+h)-f(a))/h

The Attempt at a Solution



I have done the following, and I am not sure if it is correct, though the result makes sense intuitively:

lim[h->0] (f(a+2h)-f(a+3h))/h

= 2* lim[h->0] (f(a+2h)-f(a+3h))/ (2*h)

= 2* lim[h->0] (f(a+2h)-f(a)-f(a+3h)+f(a))/ (2*h)

= 2* { lim[h->0] (f(a+2h)-f(a))/(2*h) } - 2*{lim[h->0] f(a+3h)-f(a))/ (2*h)

And here is part about which I am unsure, since I am working with multiples of h:

= 2*f'(a) - 3*{lim[h->0] f(a+3h)-f(a))/ 3*h)

= 2*f'(a) - 3*f'(a) = -f'(a)
 
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Looks fine to me.
 

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