I get two different values when calculating the tangent of a curve.

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SUMMARY

The discussion focuses on calculating the slope of the tangent line to the curve y=x-x^3 at the point (1,0) using two definitions of limits. The first method, applying the limit definition, yielded a slope of 2, while the second method resulted in -2 due to incorrect substitutions. Participants identified errors in the application of the limit definitions, specifically in substituting values for f(x) and f(1). Correcting these substitutions is essential for obtaining consistent results in derivative calculations.

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1. (a) Find the slope of the tangent line to the curve y=x-x^3 at point (1,0)
(i) using the 1st definition of a limit: lim(x->a)- (f(x)-f(a))/(x-a)
(ii) using the 2nd equation of a limit: lim(h->a)- (f(a+h)-f(a))/h​

The Attempt at a Solution


In my attempt I got two different values (the same integer value, except one's a negative).

i) (0-(x-x^3))/(x-1)= (-x+x^3)/(x-1)

Then I factored an x out of the numerator which gives me a difference of squares.

(x(x^2-1))/(x-1) = (x(x-1)(x+1))/(x-1)

Then (x-1) cancels out

=x(x+1)

Plug in lim(x->1)

=1(1+1)=2

Then I tried the other equatin:

lim(h->0)- (f(a+h)-f(a))/h

since 1 is the limit, we put 1 in as the a and it equals:

((1+h-(h+3)^3)-(1-1^3))/h

and 1 minus 1 cubed=0 so we drop the minus sign at the end along with the zero and get:

=(1+h-(h^3+3h^2+3h+1))/h

=(1+h-h^3-3h^2-3h-1)/h

=(-h^3-3h^2-2h)/h

=(-h^2-3h-2)

Then we plug in the lim(h->0)

=(-0^2-3(0)-2

lim(h->0)=-2

So as you can see, by doing both equations I get 2 and -2, but only one is tangent to the curve and the other one crosses the graph but never touches it again. I re-did these problems three times to check my calculations and nothing seems off.
 
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g4w4gg said:
1. (a) Find the slope of the tangent line to the curve y=x-x^3 at point (1,0)
(i) using the 1st definition of a limit: lim(x->a)- (f(x)-f(a))/(x-a)
(ii) using the 2nd equation of a limit: lim(h->a)- (f(a+h)-f(a))/h​


The Attempt at a Solution


In my attempt I got two different values (the same integer value, except one's a negative).

i) (0-(x-x^3))/(x-1)= (-x+x^3)/(x-1) <-- Wrong substitution



You mixed up what should be f(x) and what should be f(1) in the numerator above.

Then I tried the other equatin:

lim(h->0)- (f(a+h)-f(a))/h

since 1 is the limit, we put 1 in as the a and it equals:

((1+h-(h+3)^3)-(1-1^3))/h <-- Where did h+3 come from?

Again, you have an incorrect substitution in the second form of the derivative. Be more careful in inserting the correct values in the formulas.
 
SteamKing said:
You mixed up what should be f(x) and what should be f(1) in the numerator above.

Oh, thanks! That should straighten out the problem.

SteamKing said:
Again, you have an incorrect substitution in the second form of the derivative. Be more careful in inserting the correct values in the formulas.

The "h+3" was a typo. I ended up with the same result. Appreciate it!
 

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