redphoton Messages 12 Reaction score 0 Thread starter Aug 21, 2009 #1 If lim [A(x,y)/2^y] as y->infinity = (1/2)*[(1/2)^x] , What is A(x,y)? Last edited: Aug 21, 2009
Cyosis Homework Helper Messages 1,496 Reaction score 6 Aug 21, 2009 #2 You would want to have a term that cancels out the denominator. For example take A(x,y)=C(x)D(y), if we then take D(y)=2^y [itex]\lim_{y \to \infty}A(x,y)/2^y=\lim_{y \to \infty}C(x)=C(x)[/itex].
You would want to have a term that cancels out the denominator. For example take A(x,y)=C(x)D(y), if we then take D(y)=2^y [itex]\lim_{y \to \infty}A(x,y)/2^y=\lim_{y \to \infty}C(x)=C(x)[/itex].
redphoton Messages 12 Reaction score 0 Aug 21, 2009 #3 A(x,y) must not be y independent for y<infinity.