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If, lim [(A)/2^y] as y->infinity = (1/2)*[(1/2)^x], what is A(x)?

  1. Aug 21, 2009 #1

    lim [A(x,y)/2^y] as y->infinity = (1/2)*[(1/2)^x] ,

    What is A(x,y)?
    Last edited: Aug 21, 2009
  2. jcsd
  3. Aug 21, 2009 #2


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    You would want to have a term that cancels out the denominator. For example take A(x,y)=C(x)D(y), if we then take D(y)=2^y [itex]\lim_{y \to \infty}A(x,y)/2^y=\lim_{y \to \infty}C(x)=C(x)[/itex].
  4. Aug 21, 2009 #3
    A(x,y) must not be y independent for y<infinity.
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