If the mass of the planet is 1.38 x 10^25 kg and its radius is 4.30 x 10^7 m

Click For Summary
SUMMARY

The discussion centers on calculating the gravitational force exerted by a planet with a mass of 1.38 x 1025 kg and a radius of 4.30 x 107 m. Participants emphasize the use of Newton's law of universal gravitation, specifically the formula Fgravity = G(m1m2/r2), where G is the gravitational constant. The conversation highlights the importance of correctly applying this formula along with the principles of force and acceleration to solve the problem effectively.

PREREQUISITES
  • Understanding of Newton's law of universal gravitation
  • Familiarity with the gravitational constant (G)
  • Basic knowledge of mass and radius in physics
  • Ability to apply the formula F = ma for force and acceleration
NEXT STEPS
  • Study the derivation and application of Newton's law of universal gravitation
  • Learn how to calculate gravitational force using different masses and distances
  • Explore the concept of gravitational acceleration on different celestial bodies
  • Investigate the implications of gravitational forces in astrophysics
USEFUL FOR

Students in physics, educators teaching gravitational concepts, and anyone interested in understanding the fundamentals of gravitational force calculations.

vipson231
Messages
23
Reaction score
0
If the mass of the planet is 1.38 x 10^25 kg and its radius is 4.30 x 10^7 m...

Homework Statement



{attachment}

(all the formulas in the attachment too)

I don't know how to start this question Please help -[
 

Attachments

  • surface of the planet.jpg
    surface of the planet.jpg
    6.2 KB · Views: 480
  • formulas.jpg
    formulas.jpg
    9.4 KB · Views: 476
Physics news on Phys.org


I think that you are thinking about this too hard.

[itex]F_{gravity} = G\frac{m_{1}m_{2}}{r^{2}}[/itex]

You know G, which is a constant. You know the two masses (the planet and the apple). You know the radius of the planet. Find the force. Then, it's a simple question of [itex]\sum{\vec{F}} = m\vec{a}[/itex].
 


Oh I think i overlooked the F=Gm1m2/r^2 formula and wasn't able to work with the other formulas that were provided. Thanks for the help! =))
 

Similar threads

Replies
4
Views
2K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 62 ·
3
Replies
62
Views
5K
Replies
2
Views
3K
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 13 ·
Replies
13
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K