I If we throw a ball with initial velocity v0, is there a force?

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In projectile motion, when a ball is thrown with an initial velocity v0, there is no force acting in the x direction, as the horizontal component of velocity (v0x) remains constant throughout the flight. The only force present is in the y direction, which is due to gravity. This means that while the ball travels horizontally, it experiences no acceleration in that direction. The discussion emphasizes that without air resistance, the horizontal motion is uniform. Therefore, the ball's trajectory is determined solely by its initial velocity and the gravitational force acting downward.
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If we throw a ball with initial velocity v0, and the ball progresses in a projectile motion, ignoring air resistance, will there be a force in the x direction? If so, what is that force in the x direction's value mathematically? I know there is a force in the y direction due to gravity.
 
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No force exists in the x direction, as the value of v0x remains the same during the flight (no acceleration).
 
annamal said:
If we throw a ball with initial velocity v0, and the ball progresses in a projectile motion, ignoring air resistance, will there be a force in the x direction? If so, what is that force in the x direction's value mathematically?
More critically, what would be the direction of such a force?
 
annamal said:
If we throw a ball with initial velocity v0
That's not much of a "throw". You are just releasing the ball, which will fall straight down.
 

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