If we throw a ball with initial velocity v0, is there a force?

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SUMMARY

In projectile motion, when a ball is thrown with an initial velocity v0, there is no force acting in the x direction, as the horizontal component of velocity (v0x) remains constant throughout the flight. This is due to the absence of horizontal acceleration when ignoring air resistance. The only force present is in the y direction, attributed to gravity, which affects the vertical motion of the ball. Thus, mathematically, the force in the x direction is zero, confirming that the ball's horizontal motion is uniform.

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annamal
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If we throw a ball with initial velocity v0, and the ball progresses in a projectile motion, ignoring air resistance, will there be a force in the x direction? If so, what is that force in the x direction's value mathematically? I know there is a force in the y direction due to gravity.
 
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No force exists in the x direction, as the value of v0x remains the same during the flight (no acceleration).
 
annamal said:
If we throw a ball with initial velocity v0, and the ball progresses in a projectile motion, ignoring air resistance, will there be a force in the x direction? If so, what is that force in the x direction's value mathematically?
More critically, what would be the direction of such a force?
 
annamal said:
If we throw a ball with initial velocity v0
That's not much of a "throw". You are just releasing the ball, which will fall straight down.
 

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