If wind blows at 39 m/s over a house,

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Homework Help Overview

The discussion revolves around calculating the net force on a flat roof due to wind blowing at a speed of 39 m/s. The problem involves applying Bernoulli's principle and understanding the forces exerted by air pressure both inside and outside the house.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Bernoulli's principle and its implications for pressure differences. There are attempts to calculate the net force using given values, and questions arise regarding the necessary parameters, such as air density.

Discussion Status

The conversation is ongoing, with participants exploring different interpretations of the problem and sharing their calculations. Some guidance has been offered regarding the need to consider both internal and external air pressures, and the importance of using accurate values for air density.

Contextual Notes

There is a noted lack of information regarding the density of air, which affects the calculations. Participants express concern that variations in this value can lead to significant differences in the results.

Carnivroar
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what is the net force on the roof if its area is 320 m^2 and is flat?

I don't even know where to start.
 
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What class are you taking?
 
LawrenceC said:
What class are you taking?

physics 1

i think i have to use bernoulli's formula but i don't know how
 
What does Bernouilli's principle state?

ehild
 
ehild said:
what does bernouilli's principle state?

Ehild

1/2ρv12 + p1 = 1/2ρv22 + p2
 
Carnivroar said:
1/2ρv12 + p1 = 1/2ρv22 + p2

Correct. If you look at the equation you see that the pressure is smaller when the speed of the air is greater. The speed of air is zero below the roof in the building, v1=0 and the pressure below the roof is just the usual p1=1 atm. The wind blows over the roof, its speed is v2=39 m/s. p2 =p1 - 1/2 (rho) v22.
The pressure means the force exerted to unit surface. The air inside the building exerts F1=p1A upward force to the flat roof of area A. The air outside exerts p2A downward force to the roof. What is the net force then?

ehild
 
This is the answer I'm supposed to get

3.1×10^5

or 310000

Let me try it the way you said

Since V1 = 0 the first term goes away

P1 = 1/2 ρ 39^2 + P2

(1.225 = density of air)

101325 - 1/2 * 1.225 * 1521 = P2

101325 - 931.6125 = 100393.3875

100393.3875 * A = Fnet

100393.3875 * 320 = 32125884

Not right.

What am I doing wrong?
 
Carnivroar said:
This is the answer I'm supposed to get

3.1×10^5

or 310000

Let me try it the way you said

Since V1 = 0 the first term goes away

P1 = 1/2 ρ 39^2 + P2

(1.225 = density of air)

101325 - 1/2 * 1.225 * 1521 = P2

101325 - 931.6125 = 100393.3875

100393.3875 * A = Fnet

100393.3875 * 320 = 32125884

Not right.

What am I doing wrong?

For one thing you should really put units on stuff. For another thing you are only calculating the force on the roof exerted by the air outside the house. There's another force exerted on the roof by the air inside the house that isn't moving. They are in opposite directions.
 
You calculated the force of the blowing air, but you need the net force. Read my previous post.

ehild
 
  • #10
Oh, okay. Got it now. The problem with this question is that it doesn't give you the value for air density, so even a slight difference in the value you chose will make a difference in the big numbers. With the 1.225 I used above I was getting ~290000 then I used 1.29 and got the ~310000 I needed.

Thanks!
 
  • #11
You get more accurate result if you express the force symbolically and pug in the data at the end. The net force is
F=PA-P2A=(P1-P2)A=[P1-(P1-1/2 ρv2)]A=(1/2 ρv2)A
No need to calculate the pressure.
The density of air depends quite much on the temperature and height above sea level.
It should have been given in the problem.

ehild
 

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