If x goes very large, say infinite, what does this equation will look like

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When x approaches infinity, the behavior of the equations 1/(1+(x/H)^2)^(1/2) and 1/(1+(H/x)^2)^(1/2) can be analyzed to yield specific limits. For the first equation, the limit simplifies to 1/x, while the second equation approaches 1/x^2. This conclusion is derived by substituting large values for x and observing the resulting expressions, confirming the asymptotic behavior of these functions as x increases significantly.

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when x goes very large, say infinite, what does this equation will look like?

H is a constant

1) 1/(1+(x/H)^2)^(1/2))

2) 1/(1+(H/x)^2)^(1/2))

The answers are

1) 1/x^2

2) 1/x

But I am not too sure how to get there. Thank you
 
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1) 1 + x/h^2 is x/h^2 as x gets larger. Now you have 1 / (x/h^2)^1/2 which is h/x.

Try x = 10000 H = 5. => 4.99E-4. 5/10000 = 5E-4

2) (H/x)^2 is 1/x^2 as x gets larger? Then 1 + 1/x^2 is 1 as x gets larger. Now you have 1 / 1^1/2 which is 1.

Try x = 1000 H = 5. => .999.
 

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