If x is an accumulation point of set S and e >0

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The discussion centers on the relationship between accumulation points and limit points in the context of set theory. It establishes that if x is an accumulation point of set S and ε > 0, then there are infinitely many points within ε of x. This is equivalent to stating that if x is a limit point of set S, every neighborhood of x contains infinitely many points of S. The definitions clarify that an accumulation point requires at least one other point in the set A within any neighborhood of x, reinforcing the connection between these two concepts.

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If I were proving that "if x is an accumulation point of set S and e >0, then there are infinite number of points within e of x", is it exactly the same as saying "if x is a limit point of set S, then every neighborhood of x contains infinitely many points of S"?
 
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Seems so to me.
 
Well, a "limit point" (I cannot find the precise meaning of the phrase) has to be an accumulation point for the domain, then...
 
As I recall an accumulation point is a point in the set A where any neighborhood of x has at least one other point in A that is not x.
 
MalleusScientiarum said:
As I recall an accumulation point is a point in the set A where any neighborhood of x has at least one other point in A that is not x.

Not necessary.
 

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