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Introductory Physics Homework Help
How Does Illuminance Change With Distance in Physics Experiments?
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[QUOTE="garet122, post: 4503727, member: 454327"] Hello,[b] We had a lab in physics about the relationship between illuminance and distance. Our teacher gave use data so we make a graph of them. E is the illuminance in Lux and d is the distance in cm. (d,E) (50cm, 94 lux) (60cm, 64 lux) (70 cm, 49 lux) (80cm, 40 lux) (90 cm, 32 lux) (100cm, 26 lux) It the graph, when I connect the points it give me an inverse proportion. My objective is to find an equation. [/b] [b] What I first tried is to find an equation directly from this graph but after searching on the internet I found this formula : E=I/d^2 and this explanation : intensity is inversely proportional to the square of the distance from the source. I do not understand, in my graph d is my abscissa not d^2 . I do not understand how we can use d^2 instead of d.[/b] [/QUOTE]
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How Does Illuminance Change With Distance in Physics Experiments?
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