morphism
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By construction, a_n will fill up the entire checkerboard.
If you don't really like the juggling of indices, I suppose we can go in the 'reverse' direction. As before, let U={U_n} be a countable open cover for A. This time suppose no finite subcollection of U covers A. Then there is an a_1 in A not covered by {U_1}, and an a_2 (that is different from a_1) in A not covered by {U_1, U_2}, ..., and an a_n (that is different from a_1, ..., a_(n-1)) in A not covered by {U_1, ..., U_n}, and so on. So we have this infinite subset A'={a_1, a_2, ...} of A that cannot possibly have a limit point; for if a_infty is a limit point of A', and a_infty sits in A_k, then A_k is an open nbhd of a_infty that can only intersect A' in {a_1, ..., a_(k-1)}.
If you don't really like the juggling of indices, I suppose we can go in the 'reverse' direction. As before, let U={U_n} be a countable open cover for A. This time suppose no finite subcollection of U covers A. Then there is an a_1 in A not covered by {U_1}, and an a_2 (that is different from a_1) in A not covered by {U_1, U_2}, ..., and an a_n (that is different from a_1, ..., a_(n-1)) in A not covered by {U_1, ..., U_n}, and so on. So we have this infinite subset A'={a_1, a_2, ...} of A that cannot possibly have a limit point; for if a_infty is a limit point of A', and a_infty sits in A_k, then A_k is an open nbhd of a_infty that can only intersect A' in {a_1, ..., a_(k-1)}.
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