Im not sure if this is right so I'm making sure.

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Homework Help Overview

The discussion revolves around solving for the variable x in a fractional equation involving multiple variables and constants. Participants are attempting to clarify the setup and the nature of the equation presented.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Some participants question the validity of the equation format and whether it can be solved as presented. Others express confusion regarding the variables involved and the original problem statement.

Discussion Status

The discussion is ongoing, with participants providing guidance on how to manipulate the equation and questioning the completeness of the information provided. There is an acknowledgment of the original poster's difficulties in conveying their workings and the need for clarity in the problem setup.

Contextual Notes

Participants note that the original poster has only been instructed to find x, which raises questions about the completeness of the problem context. There is also mention of issues with posting LaTeX code and the potential for miscommunication regarding the problem's details.

Joshper14
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Homework Statement


Revised by mentor:
Solve for x
$$\frac{\frac 1 2}{\frac 3 4 } = \frac{\frac 5 6 }{\frac x 8 } $$

Note to OP: This is $$\frac{\frac 1 2}{\frac 3 4 } = \frac{\frac 5 6 }{\frac x 8 } $$

Homework Equations


$$\frac{\frac{a}{x}}{\frac{c}{1}}$$

The Attempt at a Solution


I don't know how to post my workings but here's the answer I got
X= $$\frac{BCD}{E}$$
 
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Joshper14 said:

Homework Statement


Solving for x

$$\frac{\frac{x}{b}}{\frac{c}{1}}$$
This isn't an equation, so you can't "solve for x".
Are you given some information about what the expression above is equal to? If so, that's an equation, so you can solve for x or one of the other variables.
Joshper14 said:

Homework Equations


$$\frac{\frac{a}{x}}{\frac{c}{1}}$$

The Attempt at a Solution


I don't know how to post my workings but here's the answer I got
X= $$\frac{BCD}{E}$$
In your original expression there are only the variables x, b, and c. Where did D and E come from?
 
Oh. I'm sorry you see too put what I have on paper onto this site is a pain so and remember that LaTeX code that mixed me up and forgot to put the entire 'question' up I'll upload a picture instead

The only instructions given to me from my teacher was find x. So I was tellin you I'm solving for x but you didn't understand

By the way what we are trying to find is 32
 

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To simplify both sides of this equation ##\frac {\frac A B }{\frac C D} = \frac {\frac E F}{\frac G H}##,
multiply both sides by ##\frac C D \cdot \frac G H##. That will "cancel" the fractions in the denominators, simplifying the equation above to ##\frac A B \cdot \frac G H = \frac E F \cdot \frac C D##. At this stage you can get rid of common factors ("cancel") on each side of the equation.
 
Joshper14 said:
Oh. I'm sorry you see too put what I have on paper onto this site is a pain so and remember that LaTeX code that mixed me up and forgot to put the entire 'question' up I'll upload a picture instead

The only instructions given to me from my teacher was find x. So I was telling you I'm solving for x but you didn't understand

By the way what we are trying to find is 32

Here is a snippet of that image you attached.
upload_2016-10-9_19-31-14.png
 

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