I'm really lost with average velocity and displacement

[totalanarchy]

Homework Statement

Heather and Matthew walk with an average velocity of 0.98m/s eastward. If it takes them 34 min to walk to the store, what is their displacement?

Homework Equations

V avg = Δx/Δt (since I'm looking for the displacement I changed it to) Δx=V avgΔt

The Attempt at a Solution

Δx=VavgΔt=(0.98 m/s)(34min)=33.32m East

When I looked at the back of the textbook it said 2.00km East, how did they get that number?

 

[localrob]

You should check your units. Make sure everything is canceling out correctly.

 

[totalanarchy]

I don't get that. Sorry I just started physics. I was following an example from the textbook, and I understood that. But, the questions aren't making any since. I'm starting to pull my hair trying to get the right answer.

 

[PhanthomJay]

You have the right equation. As localrob has noted, check your units for the time taken. You have the time in minutes, but you should denote the time in units of ______?____.

 

[totalanarchy]

In units of seconds right. So would I have to covert 34 minutes to seconds?

 

[PhanthomJay]

In units of seconds right. So would I have to covert 34 minutes to seconds?

Sure...(m/sec)(sec) = m

 

[totalanarchy]

Thanks I got it!

Δx=(0.98m/s)(34 min * 60 sec/min)
which gives me 1,999.2/1000 = 1.9 or 2.0km