I'm trying to compare 2 acoustic sensors

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SUMMARY

This discussion focuses on comparing two acoustic emission sensors with different sensitivity specifications: one at −150 dBre 1V/μPa and the other at -70 dB ref 1V/μbar. The user, Mark, is confused about the implications of the negative decibel values and their relationship to voltage output. Through calculations using the 20 log rule, he determines that the first sensor requires approximately 31.6 Pa to output 1 Volt, while the second requires about 316 Pa. The conversation highlights the challenges of interpreting decibel specifications and the potential for misprints in sensor data.

PREREQUISITES
  • Understanding of decibel (dB) measurements and the 20 log rule
  • Familiarity with acoustic emission sensors and their sensitivity ratings
  • Basic knowledge of pressure units, specifically Pascal (Pa) and micropascal (μPa)
  • Experience with voltage output calculations related to sensor specifications
NEXT STEPS
  • Research the differences between sensitivity ratings in acoustic sensors
  • Learn about the implications of negative decibel values in sensor specifications
  • Explore the relationship between pressure units (Pa and μbar) and their conversions
  • Investigate common issues and misprints in sensor specifications
USEFUL FOR

Engineers, acoustics researchers, and anyone involved in the selection or analysis of acoustic emission sensors will benefit from this discussion.

WarpedWatch
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Hi all,

Through my tears, I'm trying to compare two acoustic emission sensors. The first sensor has a specification that says its sensitivity is −150 dBre 1V/μPa. The other sensor says its sensitivity is -70 dB ref 1V/μbar. (Note the different units.)
Wikipedia tells me that 1 Pa = 10-5 bar. So I'm guessing 0.1Pa = 1μbar .

Okay, so it's been a long, long time since I used dB for anything. Frankly, using dB to compare things has never made any sense to me. And with that negative sign thrown in there, I'm really confused. Are they telling me that the sensor provides negative voltage output, or is it a negative sign that gets plugged into the "20 log rule". (When I plug that negative into the 20 log rule, I get insanely small numbers. ) :rolleyes:

For "20 log rule", I'm looking at this on Wikipedia: en.wikipedia.org/wiki/Decibel

If I ignore the negative and just plug and chug, I get something like this for the first sensor: Pressure needed to get 1 Volt = 10150/20 = 31.6 Pa

and this for the second sensor: Pressure needed to get 1 Volt = 1070/20 = 3162 μbar = 316 Pa

They seem to be off by an order of magnitude, but ... I noticed other sensors, which happen to have integral pre-amps, have a sensitivity rated at -24 dB ref 1V/μbar. So what to do? Anybody understand how this sort of specification is used? I'm trying to figure out how much voltage I can expect the sensors to output vs. some input of pressure. I expect the output to be in the millivolt range. but... :confused:

many thanks,
Mark
 
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The log bit is OK.

If you take the log of 3 / 1 you get 0.477
If you take the log of 1 / 3 you get -0.477

So, all the negative sign is doing is telling you that the voltage involved is smaller than the reference assuming you are using 20 log (voltage / reference voltage)

However the data seems pretty odd.
A pascal is already a very small unit. One Pascal is like 100 ml of water spread out over a square meter. Not much pressure.
A micropascal is extremely small.
To have a pressure that is 150 dB less than a micropascal gives crazy results. Could be a misprint.
 

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