- #1

- 46

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I know it's true (by graphing), but what's an algebraic way to prove it?

[tex]1+\frac{1}{3x^2}< x \tan \frac{1}{x} < \frac{1}{\sqrt{1-\frac{2}{3x^2}}}[/tex]

Thanks

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- Thread starter minifhncc
- Start date

- #1

- 46

- 0

I know it's true (by graphing), but what's an algebraic way to prove it?

[tex]1+\frac{1}{3x^2}< x \tan \frac{1}{x} < \frac{1}{\sqrt{1-\frac{2}{3x^2}}}[/tex]

Thanks

- #2

mathman

Science Advisor

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You need to specify the range for x. Let y=1/x, it will be easier to handle.

- #3

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I guess it's for 'large enough x' ie. for x>N for some N.

It's actually Euler's limit that I'm trying to prove...

- #4

disregardthat

Science Advisor

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Try to differentiate the differences.

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