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An object is a distance of 23.4 cm from the center of a silvered spherical glass Christmas tree ornament which has a diameter of 5.70 cm.

AWhat is the position of its image?

BWhat is the magnification of its image?

I think the object can be treated as a convex mirror.

s (object distance) = 23.4 cm

R = -(5.70)/2 = -2.85 cm

[tex]\frac{1}{s} + \frac{1}{s'} = \frac{2}{R}[/tex]

Using that equation, I get [tex]\frac{1}{s'} = \frac{2}{-2.85} - \frac{1}{23.4}[/tex].

Then, s' = -1.12 cm.

And, [tex]m = -\frac{s'}{s}[/tex], so m = .048.

I know for sure that -1.12 cm is not the correct answer, so most likely my second answer is also incorrect.

What did I do wrong?

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# Homework Help: Image Distance and Magnification

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