- #1

lorenz0

- 140

- 26

- Homework Statement:
- A glass plate of width ##s = 3 cm## with refraction index ##n_2 = 1.5## is in contact with water (##n_1 = 1.33##) on the left and with air on the right. An object is ##p = 10 cm## from the slab. Determine where the image of the object is formed.

- Relevant Equations:
- ##\frac{n_1}{p}+\frac{n_2}{q}=\frac{n_2-n_1}{R}##

I tried using the formula for the refraction of a spherical lens ##\frac{n_1}{p}+\frac{n_2}{q}=\frac{n_2-n_1}{R}## consider each slab as a spherical lens with curvature ##R=\infty## and by doing that I get ##\frac{1.33}{10}+\frac{1.5}{q}=0\Leftrightarrow q\approx -11.3 cm##. Since the piece of glass has a width ##s## I suppose I should count ##11.3 cm## to the left of its rightmost edge, so the object should be ##8.3 cm## to the left of the leftmost edge of the piece of glass i.e. ##1.7 cm## to the right of the original object.

Does this make sense? I had never seen before a problem with "rectangular" lenses and three different materials, so I tried to adapt what I already know to this case. Thanks

Does this make sense? I had never seen before a problem with "rectangular" lenses and three different materials, so I tried to adapt what I already know to this case. Thanks