MHB Image Markup Questions: Refresh Basics in V18 Binary Operators

[karush]

Spoiler: binary operater

image due markup questions

ok i tried to find the ?? binary operater on this but couldn't find on the given list of formats. also still need a primer on these since the last time i did a few of these was 6 years ago! don't think its a hard problem just need to refresh the basics

 

[Evgeny.Makarov]

i tried to find the ?? binary operater on this

I am not sure what you mean by ?? and by "on this". "Operator" is spelled with "o".

but couldn't find on the given list of formats.

I am not sure what you mean by formats.

A binary operator is a function of two arguments. The difference is that function applications are usually written in prefix notation: $f(x, y)$, while operators use infix notation: $x\mathop{f}y$.

 

[karush]

well the format here is 7a+5b+8
yes I saw the f(x,y) notation but I also saw a?b= notation

ok I assume the binary operator here is addition or $\oplus$ since we are adding
but I do not know what a and b is

why are they giving (a*b)=a+6b

but then it asks (2$\oplus$3)*4=
[(7(2)+5(3)+8]*4=148

or am I all botched on this

 

[topsquark]

Spoiler: binary operater

View attachment 11520

image due markup questions

ok i tried to find the ?? binary operater on this but couldn't find on the given list of formats. also still need a primer on these since the last time i did a few of these was 6 years ago! don't think its a hard problem just need to refresh the basics

You are making a mountain out of a molehill.

2 :) 3 = 7(2) + 5(3) + 8 = 14 + 15 + 8 = 37

What's 37*4?

-Dan

 

[karush]

You are making a mountain out of a molehill.

2 :) 3 = 7(2) + 5(3) + 8 = 14 + 15 + 8 = 37

What's 37*4?

-Dan

148yes but it also said a*b=a+6b see spoiler in OP so is it 37{2+6{3}}=
so the operator is a :) ?

 

[Evgeny.Makarov]

well the format here is 7a+5b+8

When a function $f$ is defined by an equation $f(a,b)=e$, I've never seen the expression $e$ referred to as "format".

ok I assume the binary operator here is addition or ⊕\oplus since we are adding
but I do not know what a and b is

One binary operator is called :). You can as well call it $f$, $\varphi$ or smiley_face. The name is completely irrelevant. Let's go with $f$. The definition $a\;: )\;b=7a+5b+8$ is equivalent to $f(a,b)=7a+5b+8$. Similarly, the second function (let's call it $g$) is defined as $g(a,b)=a+6b$. The problem asks to find $g(f(2,3),4)$.

 

[karush]

so in short we have... what we have here is a composite function of
f(a, b) or a:)b = 7a+5b+8 and g(a b) = a+6b
hence g(f(a,b),4)
so then 2 :)3 = 7(2) + 5(3) + 8 = 14 + 15 + 8 = 37
finally g(37,4) = 37+6(4)=37+24=61

 

[Evgeny.Makarov]

That's correct.

 

[karush]

10 more to go
but i think its sinking in
strange none of was ever mentioned in any of my textbooks