Impedance as seen across two terminals

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SUMMARY

The impedance between terminals 'ab' in the given circuit is definitively calculated as 27 + j9 Ω. The circuit consists of inductances valued at j10, resistances at 10, and capacitances at -j12. The discussion highlights a common approach to solving for impedance by summing the impedances of capacitors, inductors, and resistors, and then finding the equivalent impedance of their parallel connections. The initial incorrect calculation of 540/37 + 90j/37 Ω indicates a misunderstanding in the application of impedance formulas.

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Homework Statement



All the inductances in Figure P8.2.10 are j10, all the resistances are 10, and all the capacitances are -j12 . Determine the impedance between terminals 'ab'.

Ans. 27 + j9

Homework Equations





The Attempt at a Solution



I figured I should add up the impedances of the capacitors on the left and divide by 2, doing the same for the inductors and the resistors, then finding the equivalent impedance of the parallel connection of the resistors/inductors/capacitors. I keep getting an answer of 540/37 + 90j/37 Ω. Any idea what I might be doing wrong?
 

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Your answer looks correct to me. Maybe they changed component values in the question but didn't update their answer.
 
Your solution looks correct.


ehild
 

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