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Implement XNOR using NAND gates ?

  • Thread starter rclakmal
  • Start date
  • #1
76
0
what is minimum number of NAND gates to implement XOR?
i thought it in this way .first i found how many NAND gates are need to to implement XOR .
if the two input it 'A' nd 'B'
then
XOR function =A'B+AB'
so i need two NAND gates to invert A and B
then for two AND gates i need another 4 NAND gates as each AND gate need 2 NAND gates .
then for final OR gate i need another 3 NAND gate .
so this will give the XOR function .To make it XNOR i need another NAND gate

so total number of NAND gates=2+4+3+1=10

but in my MCQ question it has only
a)3 b)4 c)5 d)6

i dont how to implement XNOR in one of above answers ,totally by NAND gates .can somebody help me ?
Thanks !!!!!!!!!
 

Answers and Replies

  • #2
22
0
Three NAND gates can be combined to produce the double AND plus OR function. The rest are just those required for the invert operations.
 
  • #3
76
0
ok thnaks !!!!!!!!and i found some good ideas from wikepedia also !!!!!!!
 

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