- #1

DrummingAtom

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I just started learning Implicit Differentiation and came across an issue. I took the derivative of the circle function:

y

y' = -x / y

This all made sense until I solved the circle function for y, which gives:

y = [tex]\pm[/tex][tex]\sqrt{1 - x^2}[/tex]

For any x > 1, it's going to be complex. So, does this mean that for any x > 1 I can now compute the derivative for those complex numbers? Because plugging a x > 1 into my derivative formula I'll get a number. Any help is appreciated, thanks.

y

^{2}+ x^{2}= 1y' = -x / y

This all made sense until I solved the circle function for y, which gives:

y = [tex]\pm[/tex][tex]\sqrt{1 - x^2}[/tex]

For any x > 1, it's going to be complex. So, does this mean that for any x > 1 I can now compute the derivative for those complex numbers? Because plugging a x > 1 into my derivative formula I'll get a number. Any help is appreciated, thanks.

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