- #1

- 96

- 0

^{2}y / d

^{2}x

the equation is y

^{2}= x

^{2}

first i found the first derivative dy/dx = 2x / 2y = x / y

then i found the second using the quotient rule and got

y'' = (y - x(dy/dx)) / y

^{2}

i plugged in y' into y'' and got

y'' = (y - (x

^{2}/y)) / y

^{2}

but then im stuck after that because when i simplify i get

y'' = (y

^{2}- x

^{2}) / y

^{3}

i dont know how i can plug the original equation back in.

did i go wrong somewhere?