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the problem is to find y'' or d2y / d2x
the equation is y2 = x2
first i found the first derivative dy/dx = 2x / 2y = x / y
then i found the second using the quotient rule and got
y'' = (y - x(dy/dx)) / y2
i plugged in y' into y'' and got
y'' = (y - (x2/y)) / y2
but then im stuck after that because when i simplify i get
y'' = (y2 - x2) / y3
i dont know how i can plug the original equation back in.
did i go wrong somewhere?
the equation is y2 = x2
first i found the first derivative dy/dx = 2x / 2y = x / y
then i found the second using the quotient rule and got
y'' = (y - x(dy/dx)) / y2
i plugged in y' into y'' and got
y'' = (y - (x2/y)) / y2
but then im stuck after that because when i simplify i get
y'' = (y2 - x2) / y3
i dont know how i can plug the original equation back in.
did i go wrong somewhere?