Implicit Differentiation of tan(x-y) and Solving for y' | Step-by-Step Guide"

UsernameValid · 2012-11-05T21:12:03+00:00

tan(x-y)=y/(1+x2) When I take the derivatives of both sides, I get: sec2(x-y)(1-y')=[(1+x2)y'-2xy]/(1+x2)2

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Start date Nov 5, 2012

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The discussion focuses on the implicit differentiation of the equation tan(x-y) = y/(1+x²). The derivative of both sides is calculated, resulting in the expression sec²(x-y)(1-y') = [(1+x²)y' - 2xy]/(1+x²)². Participants confirm the differentiation steps and express satisfaction with the results. The conversation emphasizes the importance of correctly applying the chain rule and product rule in implicit differentiation. The final expression provides a pathway to solve for y' effectively.

Nov 5, 2012

UsernameValid

tan(x-y)=y/(1+x²)

When I take the derivatives of both sides, I get:
sec²(x-y)(1-y')=[(1+x²)y'-2xy]/(1+x²)²

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Nov 5, 2012

tiny-tim

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yup!

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