:Implicit Differentiation Problem - Check my work?:

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SUMMARY

The discussion focuses on the implicit differentiation of the equation xcos(y) + ycos(x) = 1. The user correctly derives the derivative dy/dx as (ysinx - cosy)/(-xsiny + cosx). Additionally, the user seeks assistance with a second problem involving the equation sqrt(xy) = 1, expressing difficulty in finding the first step for differentiation. The final answer for the first problem is confirmed as correct, while the second problem remains unresolved.

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Students studying calculus, particularly those focusing on implicit differentiation and trigonometric functions, as well as educators seeking examples for teaching these concepts.

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:Implicit Differentiation Problem -- Check my work?:

Think I placed this in the wrong forum...

I've worked it -- can someone just check my work?

Problem:

xcosy+ycos=1

My work:

[x (d/x)cosy + cosy (d/dx)x] + [y (d/dx)cosx + cosx (d/dx)y] = (d/dx) 1

-xsiny (dy/dx) + cos y - ysinx + cos x (dy/dx) = 0

-xsiny (dy/dx) + cos y = ysinx - cosy

dy/dx = (ysinx - cosy)/(-xsiny + cos x)


Meanwhile, could someone help me with this one...

squareroot (xy) = 1+(x^2)y
 
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dy/dx = (ysinx - cosy)/(-xsiny + cos x)

this final answer is right.

The second one is probably easier, have a go at it at least and we'll check the answer again?
 
Well, the problem with that one is the idea that I can't even get the first step... the derivative of sqrt (xy)
 
Square the equation.
 

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