Implicit Differentiation Question - Stuck

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SUMMARY

The discussion focuses on solving the implicit differentiation problem given by the equation y/(x-y) = x^2 + 1. The user initially attempts to differentiate and arrives at the expression y' = (3x^2 - 2xy + 1)/(2 + x^2). Feedback confirms that the user's algebraic manipulation is correct, and they are encouraged to solve for y explicitly before differentiating to verify the result. This approach reinforces the understanding of implicit differentiation and algebraic manipulation.

PREREQUISITES
  • Understanding of implicit differentiation
  • Familiarity with algebraic manipulation
  • Knowledge of calculus concepts, particularly derivatives
  • Ability to solve equations involving multiple variables
NEXT STEPS
  • Practice implicit differentiation with different equations
  • Learn how to solve equations for y before differentiation
  • Explore the application of the Chain Rule in differentiation
  • Review algebraic techniques for simplifying complex expressions
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Students studying calculus, particularly those learning about implicit differentiation and algebraic manipulation techniques. This discussion is beneficial for anyone seeking to improve their problem-solving skills in calculus.

playdohh
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Homework Statement



Use implicit differentiation to find y' given y/(x-y) = x^2+1.

Homework Equations


The Attempt at a Solution



Hi, I'm doing an online course for Calculus 12, and I have been struggling with Implicit Differentiation. I am hoping someone could maybe help me. Thanks.

I'm not positive I'm doing this right, but maybe someone can point me in the right direction. This is what I have so far

y/(x-y) = x^2+1

y=(x^2+1)(x-y)

y' = (2x)(x-y)+(x^2+1)(1-y')

y' = 2x^2-2xy+x^2-x^2y'+1-y'

This is where I get stuck and am not sure if I'm making a mistake or know what to do next. Any help would be appreciated, thank you.
 
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y/(x-y) = x^2+1

y=(x^2+1)(x-y)

y' = (2x)(x-y)+(x^2+1)(1-y')

y' = 2x^2-2xy+x^2-x^2y'+1-y'

2y'+x^2y' = 3x^2-2xy+1

y'(2+x^2) = 3x^2-2xy+1

y' = (3x^2-2xy+1)/(2+x^2)

That's what I got as my continued attempt, does that look right?
 
playdohh said:
y/(x-y) = x^2+1

y=(x^2+1)(x-y)

y' = (2x)(x-y)+(x^2+1)(1-y')
Up to here is correct. If you did the subsequent algebra correctly, you should have the right answer.

y' = 2x^2-2xy+x^2-x^2y'+1-y'

2y'+x^2y' = 3x^2-2xy+1

y'(2+x^2) = 3x^2-2xy+1

y' = (3x^2-2xy+1)/(2+x^2)

That's what I got as my continued attempt, does that look right?
In this problem, you can solve the original equation for y. Try that and then differentiate the resulting expression. See if you get the same result.
 

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