rcurrie
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Help! Keep running this and getting different answers, and none are right.
2xy^8 + 7xy = 27 at the point (3,1)
2xy^8 + 7xy = 27 at the point (3,1)
The discussion revolves around the application of implicit differentiation to the equation 2xy8 + 7xy = 27 at the point (3,1). Participants express confusion over obtaining different answers and seek clarification on the correct approach to the problem.
Participants do not appear to reach a consensus on the original question or the correct method to apply. There are competing views on whether the problem is simply verifying a point or performing implicit differentiation.
There is ambiguity regarding the specific question being addressed, and assumptions about the problem's requirements are not clearly stated. The mathematical steps provided by participants may depend on interpretations of the original problem.
Can you post the different answers with the respected work?rcurrie said:Help! Keep running this and getting different answers, and none are right.
2xy^8 + 7xy = 27 at the point (3,1)
Answers to what question? There is no question or problem here!rcurrie said:Help! Keep running this and getting different answers, and none are right.
2xy^8 + 7xy = 27 at the point (3,1)
The thread title mentions implicit differentiation. So, differentiate implicitly: $$2y^8 + 16xy^7y' + 7y + 7xy' = 0.$$ At the point $(3,1)$ that becomes $2 + 48y' + 7 + 21y' = 0$. so $69y' + 9 = 0$. That gives $y' = -\dfrac3{23}$. Is that the answer you are looking for?rcurrie said:Help! Keep running this and getting different answers, and none are right.
2xy^8 + 7xy = 27 at the point (3,1)