Implicit Differentiation with Sin

  • Thread starter Pondera
  • Start date
  • #1
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Homework Statement


1181.jpg



Homework Equations





The Attempt at a Solution


1181answers.jpg
 

Answers and Replies

  • #2
jgens
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It looks like you're not applying the product rule properly when differentiating xy^2. d(xy^2) = y^2 + 2xyy'
 
  • #3
13
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I wasn't using the product rule at all. Thank you for that! Haha.

I tried it again and got:
1181answer2.jpg


Line by line:
7= cos(xy^2)(y^2+2xyy')
7/ cos(xy^2) = (y^2+2xyy')
7/ cos(xy^2) - y^2 = 2xyy'
(7/ cos(xy^2) - y^2)(2xy) = y'
 
  • #4
gabbagabbahey
Homework Helper
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On your last step, why are you multiplying by 2xy?....Shouldn't you be dividing instead?:wink:
 
  • #5
13
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Yeah, it should be divided by our multiplied by (1/2xy). I'm not sure why I did that. :P

The rest of it looks okay though?
 
  • #6
gabbagabbahey
Homework Helper
Gold Member
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the rest looks fine :smile:
 
  • #7
13
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WOOO! It was right! Thank you very much, jgens and gabba.
 

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