Implicit function on functions composed of itself

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SUMMARY

The discussion centers on the application of the implicit function theorem to the function F(x, y), specifically addressing the conditions necessary for the equation F(F(x, y), y) = 0 to yield y as a C1 function of x near the point (0, 0). It is established that the condition dF/dy ≠ 0 is crucial for ensuring the existence of such a solution. Additionally, participants emphasize the importance of applying the chain rule correctly when differentiating F, given its recursive nature.

PREREQUISITES
  • Understanding of the implicit function theorem
  • Knowledge of C1 functions and their properties
  • Familiarity with the chain rule in calculus
  • Basic concepts of function composition
NEXT STEPS
  • Study the implicit function theorem in detail
  • Review the properties of C1 functions and their differentiability
  • Practice applying the chain rule with composite functions
  • Explore examples of function composition in multivariable calculus
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Mathematicians, calculus students, and anyone interested in advanced function analysis and the application of the implicit function theorem.

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Suppose F(x, y) is C1. F(0, 0) = 0. What conditions on F will guarantee that the equation F(F(x, y), y) = 0 can be solved for y as a C1 function of x near (0, 0) ?

would it simply be dF/dy not equal 0 ?
 
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Use the implicit function theorem. Seems you are on the right track, but F is a composition of F and y, so you would have to use the chain rule to right out dF/dy properly.
 

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