MHB Implicit Function: Why Is It a Function?

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An implicit function is defined through an equation that relates variables without explicitly solving for one in terms of the other. While some implicit functions can be expressed explicitly, such as the upper semicircle defined by the equation x^2 + f(x)^2 = 1, others, like the Lambert W function, cannot. The formal definition of a function requires a unique output for each input, which can be satisfied by implicit functions when they can be solved for one variable. However, not all implicit equations yield a single function; for instance, the equation x^2 + y^2 = 4 implies two functions, representing both the positive and negative square roots. Understanding the distinction between implicit and explicit functions is crucial in mathematical analysis.
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Why the implicit function is a function?
 
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roni said:
Why the implicit function is a function?
Can you state what you mean by an implicit function?
 
An implicit function is a function that is not (sometimes cannot be) given explicitly. The most direct way of specifying a function is to give its value for each member of its domain:
$$f:\{1,2,3\}\to\{1,4,9\};\ f(1)=1,f(2)=4,f(3)=9.$$
It is however more usual to define a function by means of a formula:
$$f:\mathbb Z\to\mathbb Z;\,f(n)=n^2.$$
Formulas can be recursive:
$$f:\mathbb Z^+\to\mathbb Z^+; f(0)=f(1)=1,f(n+2)=f(n+1)+f(n)$$
(which defines the Fibonacci sequence) or somewhat more complicated:
$$f:\mathbb R^+\to\mathbb R;\,f(x)=\int_0^\infty t^{x-1}e^{-t}\,\mathrm dt$$
(which defines the gamma function). These are all explicitly defined functions. But you can also define a function as follows:
$$f:[-1,\,1]\to[0,\,1];\,f(x)\in\{y\in[0,\,1]:y\ge0,\ x^2+y^2=1\}.$$
This defines the upper unit semicircle. In other words, $f$ is the function such that $f(x)\ge0$ satisfies the implicit equation $x^2+f(x)^2-1=0$. This is an example of an implicit function.

Of course the above implicit function can be defined explicitly as
$$f:[-1,\,1]\to[0,\,1];\,f(x)=\sqrt{1-x^2}.$$
But not all implicit functions can be redefined explicitly. One of the most important examples of such a function is the Lambert W function.

If you’re into the rigours of set theory, the formal definition of a function is as follows: Let $A$ and $B$ be sets; then a function $f$ from a set $A$ to $B$, written $f:A\to B$, is the triple $(A,B,G)$ where $G\subseteq A\times B$ such that $\forall a\in A$, $\exists b\in B$ such that $(a,b)\in G$ and $\forall a\in A,\,b_1,b_2\in B$, $(a,b_1),(a,b_2)\in G$ $\implies$ $b_1=b_2$. $A,B,G$ are called the domain, codomain, and graph respectively of the function $f$; if $(a,b)\in G$ we write $f(a)=b$.
 
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roni said:
Why the implicit function is a function?
On the contrary, an "implicit function" is NOT a function but implies a function. A "function" would be of the form y= f(x) where "f(x)" is some formula in the variable x. If, instead, we write 2y+ 8x= 5, we call that an "implicit function" because we can solve for y as a function: y= f(x)= 5/2- 4x. A bit more complicated is x^2+ y^2= 4 which implies two functions, y= f(x)= \sqrt{4- x^2} and y= g(x)= -\sqrt{4- x^2}.
 
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