Use a comparison to determine if the improper integral converges or diverges. If the integral converges, give an upper bound for the value.
Integral of d(theta) / (theta^3 + theta)^1/2 from 1 to infinity
The Attempt at a Solution
I'm not sure which function would be a good comparison to use to determine convergence or divergence. Earlier in the assignment, I ran across an equation that was dx/(9 - x^2)^1/2 which was arcsin(x/3), and since this is +, it'd be arccos - however that was with x^2 and this is theta^3, I'm not sure if that would be a direct comparison or not.
Any help would be appreciated, thanks.