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Improper Integral using Comparison to determine Convergence/Divergence

  • Thread starter MiDnite89
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Homework Statement



Use a comparison to determine if the improper integral converges or diverges. If the integral converges, give an upper bound for the value.

Integral of d(theta) / (theta^3 + theta)^1/2 from 1 to infinity

Homework Equations



N/A

The Attempt at a Solution



I'm not sure which function would be a good comparison to use to determine convergence or divergence. Earlier in the assignment, I ran across an equation that was dx/(9 - x^2)^1/2 which was arcsin(x/3), and since this is +, it'd be arccos - however that was with x^2 and this is theta^3, I'm not sure if that would be a direct comparison or not.

Any help would be appreciated, thanks.
 

Answers and Replies

  • #2
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∫ dx/√(9 - x2) is arcsin(x/3) + C, but a + between the two terms in the denominator would not involve arccosine in the integral but instead, arctangent. In fact, that integral could also be written as -arccos(x/3) + C. Most integrals involving arcsine or arccosine like this one can differ only by a sign and constant.
For your problem, you don't have to actually find the integral, just find another integral with which to compare it.

Start with the comparison θ3 + θ > θ (for θ > 1) and work with it until you can make the left side look like your integrand 1/√(θ3 + θ)
 
Last edited:

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