Improving Photodiode Circuit Performance: Understanding Slow Rise Time Issues

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Discussion Overview

The discussion focuses on the performance issues of a photodiode circuit, specifically addressing the unexpectedly slow rise time of approximately 130ms. Participants explore potential causes and solutions related to circuit design, including biasing and component values.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant notes that the rise time of their photodiode circuit is significantly slower than expected, despite the photodiode's specifications indicating a rise time of 200µs.
  • Another participant questions the use of a 1M ohm feedback resistor, suggesting it may be too large for the desired speed of the circuit.
  • A participant explains that the large feedback resistor was chosen to achieve a specific output voltage before a voltage divider, indicating a calculated current of ~5µA from the photodiode.
  • One participant suggests that to improve the speed of the circuit, the photodiode should be reverse biased to reduce capacitance and the feedback resistance should be lowered to enhance the RC time constant.
  • Participants discuss the importance of considering the input capacitance of the opamp and PCB parasitic trace capacitance in RC calculations.

Areas of Agreement / Disagreement

Participants express differing views on the appropriateness of the circuit design choices, particularly regarding the feedback resistor value and the need for biasing the photodiode. No consensus is reached on the best approach to resolve the slow rise time issue.

Contextual Notes

Limitations include the lack of biasing for the photodiode, which some participants indicate may be necessary, and the potential impact of component values on circuit performance that remains unresolved.

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Hi,

I have a photodiode circuit (attached), where a photodiode is hooked up to a current to voltage opamp connected to a voltage divider. This circuit works as intended: when there is light, Vo ~ 3.3V, and when there is no light, Vo ~ 0.3V. However, when I measured the rise time of this circuit, I found out that it takes ~130ms to switch, which is much slower than I anticipated. The photodiode's spec says that its rise and fall time is 200us, and although I am not in the same operating condition, I expect the delay to be in the same order of magnitude, give or take. Therefore, if any1 has any idea on this, please let me know.

Thanks.

[opamp] http://focus.ti.com/lit/ds/symlink/opa657.pdf
[photodiode] http://catalog.osram-os.com/catalogue/catalogue.do;jsessionid=D791D4FBE4D533287FAB36C83ADE1303?act=downloadFile&favOid=020000030000c448000100b6
 

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Is that 1M for the feedback resistor - that's rather large.
You haven't show the bias supply for the photodiode, are you just using the opamp input to bias it?
 
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Yes, that's 1M ohm. The reason why it's made large is because I wanted the output voltage BEFORE the voltage divider to be 5V (saturating the opamp) and then step it down to 3.3V AFTER the voltage divider. In fact, based on my calculation, the current generated by the photodiode is ~5uA. So to get 5V, I did, 5V = 5u*1M.

It should be ok even if the Rf is large because it will simply saturate the opamp and get 5V as mentioned before.

As for biasing, you are correct and I didn't bias the photodiode. I didn't realize you have to. I saw a proposed design from Sharp that used a simliar circuit so I thought it was fine. It's on page 3 Figure 6 of the link below

http://vorlon.case.edu/~flm/eecs245/Datasheets/Sharp%20photodevices.pdf
 
Last edited by a moderator:
To speed up your photodetector I --> V circuit, you need to reverse bias the diode (to lower its capacitance) and lower the feedback resistance (to speed up the associated RC time constant). No circuit with a 1Meg resistor in it is going to be fast. Don't forget to include the input capacitance of the opamp and the PCB parasitic trace capacitance in your RC calculations.
 
Thanks for your suggestion. I will try them out.
 

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