Impulse and Force-Time Graph Problem

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jmm
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Homework Statement


Force-time graph with F_x on the vertical axis and t (ms) on the horizontal axis from 0 to 10. F rises linearly from 0 to F_max at t = 2 ms, then falls linearly to 0 at t = 8 ms, and stays at zero until t = 10 ms.

In the figure , what value of Fmax gives an impulse of 7.1 Ns


Homework Equations


Equation: impulse I, as a vector, equals the integral from t1 to t2 of force F dt.



The Attempt at a Solution


Impulse is the integral of force with respect to time which is the same the area under the force-time graph which is given by the area of the triangle: 0.5*Fmax*8s

7.1 Ns = 4s * Fmax
Fmax = 1.775 N

However that's not the right answer. Where did I go wrong? Thanks!