A baseball has mass 0.145 kg. A. If the velocity of a pitched ball has a magnitude of 45.0 m/s and the battered ball's velocity is 55.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball. delta p = m*delta v = m*(v2 -v1) = .145 kg (-55.0 m/s - 45.0 m/s) = -14.5 kg*m/s B. Find magnitude of impulse applied to it by bat. J = F*delta t = delta p = -14.5 kg*m/s ?? Is it the same as the above? C. If the ball remains in contact with the bat for 2.00 ms, find the magnitude of the average force applied by bat. J = Avg. F*delta t delta t = 2.00 ms(1s/1000 ms) = .002 s Avg. F = J/delta t = (-14.5 kg*m/s)/.002 s = -7250 N ? Thanks.