A baseball has mass 0.145 kg.(adsbygoogle = window.adsbygoogle || []).push({});

A. If the velocity of a pitched ball has a magnitude of 45.0 m/s and the battered ball's velocity is 55.0 m/s in the opposite direction, find the magnitude of the change in momentum of the ball.

delta p = m*delta v = m*(v2 -v1) = .145 kg (-55.0 m/s - 45.0 m/s) = -14.5 kg*m/s

B. Find magnitude of impulse applied to it by bat.

J = F*delta t = delta p = -14.5 kg*m/s ?? Is it the same as the above?

C. If the ball remains in contact with the bat for 2.00 ms, find the magnitude of the average force applied by bat.

J = Avg. F*delta t

delta t = 2.00 ms(1s/1000 ms) = .002 s

Avg. F = J/delta t = (-14.5 kg*m/s)/.002 s = -7250 N ?

Thanks.

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# Homework Help: Impulse, Momentum, and Baseball

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