- #1
atavistic
- 106
- 0
Homework Statement
A block of mass 200g is suspended through a vertical spring.The spring is stretched by 1cm when the block is in equilibrium.A particle of mass 120g is dropped on the block from a height of 45cm.The particle sticks to the block after the impact.Find the max extension of the spring.
The attempt at a solution
Well in the beginning my aim was to find the force constant k.But i am stuck ..should i use k|x| = mg or work done by spring = loss in gravitational PE i.e (kx^2)/2 = mgx.Getting diff result in both. After that I must find out the velocity of the system due to the impulse but how?Then i can apply conservation of mechanical energy I guess i.e KE just after the collision + spring PE_1 = mgh + spring PE_2. (where spring PE_1 is the spring PE before the impact and spring PE_2 is spring PE when it is max stretched.)
Plz help
A block of mass 200g is suspended through a vertical spring.The spring is stretched by 1cm when the block is in equilibrium.A particle of mass 120g is dropped on the block from a height of 45cm.The particle sticks to the block after the impact.Find the max extension of the spring.
The attempt at a solution
Well in the beginning my aim was to find the force constant k.But i am stuck ..should i use k|x| = mg or work done by spring = loss in gravitational PE i.e (kx^2)/2 = mgx.Getting diff result in both. After that I must find out the velocity of the system due to the impulse but how?Then i can apply conservation of mechanical energy I guess i.e KE just after the collision + spring PE_1 = mgh + spring PE_2. (where spring PE_1 is the spring PE before the impact and spring PE_2 is spring PE when it is max stretched.)
Plz help
Last edited: