In a popular amusement-park ride, a cylinder of radius 2.00 m is set in rota

Click For Summary

Homework Help Overview

The problem involves a rotating amusement-park ride where a cylinder's radius is given, and the angular speed is specified. The scenario requires determining the minimum coefficient of friction necessary to prevent riders from slipping against the wall of the cylinder after the floor drops away.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for calculating the coefficient of friction, with some questioning the placement of parentheses in the equation. There are attempts to verify the calculations and explore different numerical results.

Discussion Status

The discussion has seen various calculations and interpretations of the formula. Some participants have expressed uncertainty about the correctness of their answers and the reliability of answer keys. A specific numerical value was eventually confirmed as correct by one participant.

Contextual Notes

There appears to be confusion regarding the calculations and the accuracy of provided answer keys, which may influence participants' confidence in their results.

lettertwelve
Messages
54
Reaction score
0
[SOLVED] In a popular amusement-park ride, a cylinder of radius 2.00 m is set in rota

Homework Statement



In a popular amusement-park ride, a cylinder of radius 2.00 m is set in rotation at an angular speed of 6.00 rad/s, as shown in Figure 7-20 (http://www.webassign.net/sfhs99/7-20.gif). The floor then drops away, leaving the riders suspended against the wall in a vertical position. What minimum coefficient of friction between a rider's clothing and the wall of the cylinder is needed to keep the rider from slipping?

Homework Equations



mu = g/omega^2*R

The Attempt at a Solution



mu= 9.8/36*2 = .54

but it says I am incorrect..
 
Physics news on Phys.org
You have it parenthesized wrong. mu=g/(omega^2*R), mu=9.8/(36*2). That's not 0.54.
 
Dick said:
You have it parenthesized wrong. mu=g/(omega^2*R), mu=9.8/(36*2). That's not 0.54.

so it's .14

i got that answer before, but its still incorrect.
 
It looks pretty right to me. Answer keys are not always correct. But then I'm not always correct either. Did you try 0.13611111...
 
Dick said:
It looks pretty right to me. Answer keys are not always correct. But then I'm not always correct either. Did you try 0.13611111...

i typed in 0.13611111, and it worked! thank you!
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
6K
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
11K
  • · Replies 6 ·
Replies
6
Views
10K
  • · Replies 6 ·
Replies
6
Views
5K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 2 ·
Replies
2
Views
2K