# In a popular amusement-park ride, a cylinder of radius 2.00 m is set in rota

1. Nov 7, 2007

### lettertwelve

[SOLVED] In a popular amusement-park ride, a cylinder of radius 2.00 m is set in rota

1. The problem statement, all variables and given/known data

In a popular amusement-park ride, a cylinder of radius 2.00 m is set in rotation at an angular speed of 6.00 rad/s, as shown in Figure 7-20 (http://www.webassign.net/sfhs99/7-20.gif). The floor then drops away, leaving the riders suspended against the wall in a vertical position. What minimum coefficient of friction between a rider's clothing and the wall of the cylinder is needed to keep the rider from slipping?

2. Relevant equations

mu = g/omega^2*R

3. The attempt at a solution

mu= 9.8/36*2 = .54

but it says im incorrect..

2. Nov 7, 2007

### Dick

You have it parenthesized wrong. mu=g/(omega^2*R), mu=9.8/(36*2). That's not 0.54.

3. Nov 7, 2007

### lettertwelve

so it's .14

i got that answer before, but its still incorrect.

4. Nov 7, 2007

### Dick

It looks pretty right to me. Answer keys are not always correct. But then I'm not always correct either. Did you try 0.13611111....

5. Nov 8, 2007

### lettertwelve

i typed in 0.13611111, and it worked! thank you!!!!