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In a popular amusement-park ride, a cylinder of radius 2.00 m is set in rota

  1. Nov 7, 2007 #1
    [SOLVED] In a popular amusement-park ride, a cylinder of radius 2.00 m is set in rota

    1. The problem statement, all variables and given/known data

    In a popular amusement-park ride, a cylinder of radius 2.00 m is set in rotation at an angular speed of 6.00 rad/s, as shown in Figure 7-20 (http://www.webassign.net/sfhs99/7-20.gif). The floor then drops away, leaving the riders suspended against the wall in a vertical position. What minimum coefficient of friction between a rider's clothing and the wall of the cylinder is needed to keep the rider from slipping?

    2. Relevant equations

    mu = g/omega^2*R

    3. The attempt at a solution

    mu= 9.8/36*2 = .54

    but it says im incorrect..
     
  2. jcsd
  3. Nov 7, 2007 #2

    Dick

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    You have it parenthesized wrong. mu=g/(omega^2*R), mu=9.8/(36*2). That's not 0.54.
     
  4. Nov 7, 2007 #3
    so it's .14

    i got that answer before, but its still incorrect.
     
  5. Nov 7, 2007 #4

    Dick

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    It looks pretty right to me. Answer keys are not always correct. But then I'm not always correct either. Did you try 0.13611111....
     
  6. Nov 8, 2007 #5
    i typed in 0.13611111, and it worked! thank you!!!!
     
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