In an ionic equation, how do you know what pairs with what? For example:?

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Discussion Overview

The discussion focuses on understanding how to determine the combinations of ions in an ionic equation, specifically in the context of predicting the formation of solids from aqueous solutions. Participants explore the reasoning behind the final ionic equation and the role of solubility rules in identifying precipitates.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions how to determine the order of ions in the final ionic equation, suggesting that the order may not matter.
  • Another participant notes that K+ and NO3- should be considered spectator ions and removed from the net ionic equation.
  • There is a query about how to know which combinations of ions will form a solid, specifically regarding the formation of PbI2 from aqueous Pb2+ and I- ions.
  • A participant mentions the need to check combinations of cations and anions to identify possible salts and their solubility.
  • Participants discuss the application of solubility rules to determine which salts are insoluble and will precipitate.

Areas of Agreement / Disagreement

Participants generally agree on the importance of solubility rules in predicting precipitate formation, but there is no consensus on the specifics of how to apply these rules or the implications for the order of ions in the equation.

Contextual Notes

Limitations include potential misunderstandings of solubility rules and the need for clarification on how these rules apply to specific combinations of ions.

Who May Find This Useful

This discussion may be useful for students learning about ionic equations, solubility, and precipitation reactions in chemistry.

land_of_ice
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molecular:
Pb(NO3)2 (aq) + 2 KI (aq) ----->2KNO3 (aq) + Pbl2 (s)
Ionic equation
Pb2+ (aq) + 2NO3- (aq) + 2 K (aq) + 2 I- (aq)----->2K+ (aq)+ 2NO3- (aq) + PbI2 (s)

I know why they break apart in the ionic part, its because ionic things aer broken up, but how would you know that they join together to form 2K+ (aq)+ 2NO3- (aq) + PbI2 (s) at the end? like in that order?

and one more question, how do you know that when certain things join together, that they form a solid, such as they way PbI2 (s) forms, because at first Pb was (aq), and I2 was (aq) also
 
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land_of_ice said:
how would you know that they join together to form 2K+ (aq)+ 2NO3- (aq) + PbI2 (s) at the end? like in that order?

Order doesn't matter, 2NO3- (aq) + PbI2 (s) + 2K+ (aq) is perfectly valid. Note that K+ and NO3- should be removed, as they are just spectators.

how do you know that when certain things join together, that they form a solid, such as they way PbI2 (s) forms, because at first Pb was (aq), and I2 was (aq) also

Do you know solubility rules?
 
Borek said:
Order doesn't matter, 2NO3- (aq) + PbI2 (s) + 2K+ (aq) is perfectly valid. Note that K+ and NO3- should be removed, as they are just spectators.



Do you know solubility rules?

Can you explain how it uses the solubility rules? Because That's the part I don't understand. I know the solubility rules, just not how the solubility rules affect it and thanks so much for the help
 
You have four ions present: K+, Pb2+, I-, NO3-. Basically you check all combinations that can create a salt (that means cation and anion) and you check if it is soluble or not.

In this particular case there are following combinations possible (do you see why?):
K+ & I-
K+ & NO3-
Pb2+ & I-
Pb2+ & NO3-

Try to apply solubility rules to find out which of the possible salts is insoluble and will precipitate.
 

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