In an ionic equation, how do you know what pairs with what? For example:?

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land_of_ice
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molecular:
Pb(NO3)2 (aq) + 2 KI (aq) ----->2KNO3 (aq) + Pbl2 (s)
Ionic equation
Pb2+ (aq) + 2NO3- (aq) + 2 K (aq) + 2 I- (aq)----->2K+ (aq)+ 2NO3- (aq) + PbI2 (s)

I know why they break apart in the ionic part, its because ionic things aer broken up, but how would you know that they join together to form 2K+ (aq)+ 2NO3- (aq) + PbI2 (s) at the end? like in that order?

and one more question, how do you know that when certain things join together, that they form a solid, such as they way PbI2 (s) forms, because at first Pb was (aq), and I2 was (aq) also
 
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land_of_ice said:
how would you know that they join together to form 2K+ (aq)+ 2NO3- (aq) + PbI2 (s) at the end? like in that order?

Order doesn't matter, 2NO3- (aq) + PbI2 (s) + 2K+ (aq) is perfectly valid. Note that K+ and NO3- should be removed, as they are just spectators.

how do you know that when certain things join together, that they form a solid, such as they way PbI2 (s) forms, because at first Pb was (aq), and I2 was (aq) also

Do you know solubility rules?
 
Borek said:
Order doesn't matter, 2NO3- (aq) + PbI2 (s) + 2K+ (aq) is perfectly valid. Note that K+ and NO3- should be removed, as they are just spectators.



Do you know solubility rules?

Can you explain how it uses the solubility rules? Because That's the part I don't understand. I know the solubility rules, just not how the solubility rules affect it and thanks so much for the help
 
You have four ions present: K+, Pb2+, I-, NO3-. Basically you check all combinations that can create a salt (that means cation and anion) and you check if it is soluble or not.

In this particular case there are following combinations possible (do you see why?):
K+ & I-
K+ & NO3-
Pb2+ & I-
Pb2+ & NO3-

Try to apply solubility rules to find out which of the possible salts is insoluble and will precipitate.