Inclined Plane Force w/ Friction

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SUMMARY

The discussion focuses on calculating the coefficient of static friction for a mass of 11 kg on an inclined plane with friction, subjected to a perpendicular force of 59 Newtons. The incline angle at which the mass begins to slide is 56.7 degrees. Participants emphasize the importance of drawing a free body diagram (FBD) to resolve gravitational forces into sine and cosine components, leading to the conclusion that the coefficient of static friction is calculated as 0.762 using the formula mg sin(theta) / normal force, where the normal force is determined to be 118 N.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of free body diagrams (FBD)
  • Familiarity with trigonometric functions in physics
  • Concept of static friction and its calculation
NEXT STEPS
  • Study the derivation of static friction coefficients in inclined planes
  • Learn how to effectively draw and analyze free body diagrams (FBD)
  • Explore the effects of varying angles on frictional forces
  • Investigate the relationship between normal force and applied forces in static scenarios
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Students in physics courses, educators teaching mechanics, and anyone interested in understanding forces on inclined planes with friction.

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Homework Statement


A mass of m = 11 kg is placed on incline plane with friction. A force with a magnitude of F = 59 Newtons is applied downward, perpendicular to the plane at all times. As the angle of the incline is increased from zero degrees it remains static until it reaches an angle of x = 56.7 degrees when it begins to slide. What is the coefficient of static friction for this situation?

I'm guessing that I sum up the forces as I would for a non-friction inclined plane problem, and then divide by the 59 N that they give you? Would I be assuming correctly?
 
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The normal reaction on the block due to the plane is not 59 N. Draw a complete FBD and you'll see. (Resolve the grav. force on the block into its sine and cosine components)
 
sArGe99 said:
The normal reaction on the block due to the plane is not 59 N. Draw a complete FBD and you'll see. (Resolve the grav. force on the block into its sine and cosine components)

I believe the answer is .762. mg sin theta / 118, where 118 is the calculated normal force?
 

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