Inclined Plane Momentum Conservation with Frictionless Horizontal Surface

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Discussion Overview

The discussion revolves around the dynamics of a cube sliding down a frictionless inclined plane that is itself on a frictionless horizontal surface. Participants explore the implications of momentum conservation in this scenario, particularly whether the inclined plane would also accelerate as the cube descends.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant notes that the cube accelerates down the inclined plane due to gravitational force, specifically F = mgsin(theta), where theta is the angle of the incline.
  • Another participant suggests that writing out the force equations would clarify the situation, implying a straightforward application of physics principles.
  • It is proposed that as the cube descends, it would experience vertical free fall while the inclined plane would move horizontally, as there are no restrictions on its motion.
  • A later reply emphasizes that the cube is not in free fall, as the inclined plane exerts a force on it, indicating a need for further clarification on the forces at play.
  • Another participant asserts that both the cube and the inclined plane will move apart horizontally due to Newton's Third Law, alongside the vertical motion of the cube.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the forces acting on the cube and the inclined plane, leading to an unresolved discussion regarding the specifics of their interactions and the implications for momentum conservation.

Contextual Notes

Some assumptions regarding the system's constraints and the definitions of motion are not fully articulated, which may affect the clarity of the discussion.

leonidas24
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Consider the classical physics problem of a cube sitting atop a frictionless inclined plane. Of course, this cube will accelerate down the plane with acceleration dictated by F = mgsin(theta), where theta is the angle between the inclined plane and the horizontal surface.

Easy enough.

Now, my question is this; if the inclined plane was itself sitting atop a frictionless, horizontal plane, would it too accelerate in some direction as the cube slides down its surface? In order to conserve momentum, for instance?
 
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Just write out the force equation and that should do it. Have faith, my lad! Physics works.
 
The cube would have a simple vertical free fall and the inclined plane would move out of its way as the cube goes down since it doesn't have any restriction.
 
leonidas24 said:
Now, my question is this; if the inclined plane was itself sitting atop a frictionless, horizontal plane, would it too accelerate in some direction as the cube slides down its surface? In order to conserve momentum, for instance?
Of course.

jack action said:
The cube would have a simple vertical free fall and the inclined plane would move out of its way as the cube goes down since it doesn't have any restriction.
The cube is not in free fall. The incline exerts a force on it.
 
The cube and the ramp will move apart horizontally - Newton's Third Law - in addition to the cube moving vertically.
 

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