Inclined plane translational velocity

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Homework Help Overview

The problem involves a hollow cylinder rolling down an inclined plane, with a focus on determining its translational velocity at the bottom after traveling a specified distance. The subject area includes concepts from mechanics, specifically energy conservation and rotational motion.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of energy principles, with some attempting to relate height, distance, and velocity through various equations. Questions arise regarding the definitions of translational and angular velocities, as well as the relationship between them.

Discussion Status

The discussion is ongoing, with multiple participants contributing different perspectives on the energy conservation approach. Some participants are seeking clarification on the translational velocity specifically, while others are reiterating the energy equations without reaching a consensus on the final interpretation.

Contextual Notes

There appears to be some confusion regarding the definitions and relationships between translational and angular velocities, as well as the specific parameters involved in the calculations. The problem setup includes a specific mass, diameter, and incline angle, but further details may be necessary for complete clarity.

davidelete
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Homework Statement


A hollow cylinder with a mass of 1.2 kilograms and a diameter of .25 m rolls down an inclined plane angled at 35 degrees. What is its translational velocity at the bottom of the incline plane if the distance traveled is 3 meters?

Homework Equations


v=\sqrt{gh}
?

The Attempt at a Solution


sin35=h/3m
h=1.72m
v=\sqrt{9.8*1.72}
4.1 m/s
 
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According to the conservation of energy,
mgh = 1/2*Iω^2 + 1/2*m*v^2.
here h = d*sinθ. The angular velocity v =ω*R, where R is the radius of the cylinder.
 
Last edited:
rl.bhat said:
According to the conservation of energy,
mgh = 1/2*Iω^2 + 1/2*m*v^2.
here h = d*sinθ. The angular velocity ω = v*R, where R is the radius of the cylinder.

I need translational velocity.
 
davidelete said:
I need translational velocity.
v is the translational velocity of the center of mass.
 
rl.bhat said:
v is the translational velocity of the center of mass.

Please explain more.
 
According to the conservation of energy
K1 + U1 = K2 + U2
0 + mgh = 1/2*m*v^2 + 1/2I*ω^2.
mgdsinθ = 1/2*m*v^2 + 1/2MR^2(v/R)^2 + 0
So mgdsinθ = mv^2.
So what ever you have calculated is the required result.
 

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