Inclined plane translational velocity

[davidelete]

Homework Statement

A hollow cylinder with a mass of 1.2 kilograms and a diameter of .25 m rolls down an inclined plane angled at 35 degrees. What is its translational velocity at the bottom of the incline plane if the distance traveled is 3 meters?

Homework Equations

v=$$\sqrt{gh}$$
?

The Attempt at a Solution

sin35=h/3m
h=1.72m
v=$$\sqrt{9.8*1.72}$$
4.1 m/s

 

[rl.bhat]

According to the conservation of energy,
mgh = 1/2*Iω^2 + 1/2*m*v^2.
here h = d*sinθ. The angular velocity v =ω*R, where R is the radius of the cylinder.

 

[davidelete]

According to the conservation of energy,
mgh = 1/2*Iω^2 + 1/2*m*v^2.
here h = d*sinθ. The angular velocity ω = v*R, where R is the radius of the cylinder.

I need translational velocity.

 

[rl.bhat]

I need translational velocity.

v is the translational velocity of the center of mass.

 

[davidelete]

v is the translational velocity of the center of mass.

Please explain more.

 

[rl.bhat]

According to the conservation of energy
K1 + U1 = K2 + U2
0 + mgh = 1/2*m*v^2 + 1/2I*ω^2.
mgdsinθ = 1/2*m*v^2 + 1/2MR^2(v/R)^2 + 0
So mgdsinθ = mv^2.
So what ever you have calculated is the required result.