Inclined plane w/ friction problem

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SUMMARY

The problem involves a 5-kg block sliding down an inclined plane at a 23-degree angle with a coefficient of kinetic friction of 0.20. The acceleration of the block is calculated using the formula a = gsin(23) - 0.20gcos(23), resulting in an acceleration of 2.02 m/s². This calculation accurately accounts for both gravitational force and frictional force acting on the block. The approach and final answer were confirmed as correct by participants in the discussion.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Basic trigonometry for calculating sine and cosine values
  • Knowledge of kinetic friction and its coefficient
  • Familiarity with inclined plane physics
NEXT STEPS
  • Review the derivation of forces on an inclined plane
  • Learn about the effects of different coefficients of friction on acceleration
  • Explore advanced problems involving multiple forces on inclined planes
  • Study the application of Newton's laws in non-vertical motion scenarios
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of inclined plane problems with friction.

peachy112girl
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Homework Statement


A 5-kg block is sliding down an inclined plane. The angle between the incline and the horizontal is 23 degrees. The coefficient of kinetic friction is 0.20. What is the acceleration of the block, in m/s2?


Homework Equations





The Attempt at a Solution


Here's the answer that I got, but I'm not sure if it's correct:

ma = mgsin23 - 0.20mgcos23
a= gsin23 - .20gcos23 = 2.02 m/s2
 
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this looks good to me!
 

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