Increasing current by a factor of 48

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SUMMARY

To increase the current in a circuit by a factor of 48, the voltage must also be increased by the same factor, resulting in a voltage increase of 48.0. This conclusion is derived from the relationship defined by Ohm's Law, where current (I) is equal to voltage (V) divided by resistance (R). The equation used in the discussion confirms that multiplying the current by 48 necessitates a proportional increase in voltage to maintain the same resistance. Therefore, the correct answer to the homework question is E. 48.0.

PREREQUISITES
  • Understanding of Ohm's Law (V = I * R)
  • Basic knowledge of electrical circuits
  • Familiarity with units of measurement for voltage, current, and resistance
  • Ability to manipulate algebraic equations
NEXT STEPS
  • Study advanced applications of Ohm's Law in complex circuits
  • Explore the effects of varying resistance on current and voltage
  • Learn about power calculations in electrical circuits (P = V * I)
  • Investigate the implications of circuit design on current flow
USEFUL FOR

Electrical engineering students, hobbyists working with circuits, and professionals involved in circuit design and analysis will benefit from this discussion.

jst
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Homework Statement



Given a circuit with one battery and a single resistor. The circuit has a battery voltage of V, a total current I and resistance R. To increase the current by a factor of 48.0 then by what factor will the voltage need to be increased?

A. 12.0
B. 90.0
C. 65.0
D. 2.00
E. 48.0


Homework Equations



Amps = Volts/Ohms

The Attempt at a Solution



I think it's 48.

Amps = Volts/Ohms
48* Amps = (Volts * x)/Ohms

48*Amps * Ohms = Volts * x

48 * Volts = Volts * x

x = 48


Does this look OK?

Thanks a lot,

Jason
 
Physics news on Phys.org
yes, that looks correct.
 
dmoravec said:
yes, that looks correct.

Thanks a lot.
 

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