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Increasing current by a factor of 48

  1. Feb 14, 2007 #1

    jst

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    1. The problem statement, all variables and given/known data

    Given a circuit with one battery and a single resistor. The circuit has a battery voltage of V, a total current I and resistance R. To increase the current by a factor of 48.0 then by what factor will the voltage need to be increased?

    A. 12.0
    B. 90.0
    C. 65.0
    D. 2.00
    E. 48.0


    2. Relevant equations

    Amps = Volts/Ohms

    3. The attempt at a solution

    I think it's 48.

    Amps = Volts/Ohms
    48* Amps = (Volts * x)/Ohms

    48*Amps * Ohms = Volts * x

    48 * Volts = Volts * x

    x = 48


    Does this look OK?

    Thanks a lot,

    Jason
    1. The problem statement, all variables and given/known data



    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Feb 14, 2007 #2
    yes, that looks correct.
     
  4. Feb 14, 2007 #3

    jst

    User Avatar

    Thanks a lot.
     
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