(adsbygoogle = window.adsbygoogle || []).push({}); The problem statement, all variables and given/known data

http://s2.ipicture.ru/uploads/20120117/ReWSCD1f.jpg

The attempt at a solution

[tex]\frac{\partial P}{\partial y}=\frac{2y}{x^3}[/tex]

[tex]\frac{\partial Q}{\partial x}=\frac{2y}{x^3}[/tex]

[tex]\frac{\partial Q}{\partial x}=\frac{\partial P}{\partial y}[/tex]

According to my notes: Both functions are continuous, except at x=0.

My tentative explanation: This is due to the denominator in [itex]\frac{2y}{x^3}[/itex] which will make the fraction equal to infinity at x=0. Therefore the functions won't be continuous at x=0. Is this explanation correct?

Apparently, at this stage, i am free to choose whatever path i please. I'm going to start from path y=1 (1,1) to (2,1) and then move up the path x=2 (2,1) to (2,2).

Then, i do direct substitution:

[tex]I=\int^2_1\frac{11}{x^3}\,dx+\int^2_1 -\frac{5}{4}\,ydy[/tex]

Is this correct?

After i did the integration, i get the final answer: [itex]-\frac{87}{8}[/itex] but it's wrong.

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# Homework Help: Independence of path of line integral

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