stunner5000pt
- 1,447
- 5
a few questions
a) can a 3x4 matrix have independent columns? rows? Explain
if i were to reduce to row echelon form then i could potentially have 4 leading 1s. I m not quite sure about this.
if i were to reduce this 3 x 4 matrix into row echelon form then the number of rows is less than the number of variables. SO the answer is no.
b) if A is a 4 x3 matrix and rank A = 2, can A have independent columns? rows? Explain
ok rank A means that out of the 4 rows only 2 are non zero when A is in row echelon form. Potentially 3 leading 1s in the columns so at least 2 of the columns may be independent on each other. So independent columns are not possible.
Indepednat rows not possible.
c) Can a non square matrix has its rows indepedant and its columns independent?
im not sure about this. If A (MxN) then for m rows A has n unknowns so it is not possible to have indepdnatn rows. As for the columns i ahve no idea.
If A is m x n and B is n x m show taht AB = 0 iff [itex]col B \subseteq null A[/itex]
suppose AB = 0
let columns of B = [itex]C_{i}[/itex]
rows of A = [itex]R_{i}[/itex]
for all i
then [tex]R_{i} C_{i} = 0 [/itex] if Ci = 0 for all i. Thus Ci belongs to null A<br /> Suppose [tex]col B \subseteq null A[/tex]<br /> then anything times a column of B is zero. Thus AB = 0 <br /> Is this proof adequate?<br /> <br /> your input is greatly appreciated![/tex]
a) can a 3x4 matrix have independent columns? rows? Explain
if i were to reduce to row echelon form then i could potentially have 4 leading 1s. I m not quite sure about this.
if i were to reduce this 3 x 4 matrix into row echelon form then the number of rows is less than the number of variables. SO the answer is no.
b) if A is a 4 x3 matrix and rank A = 2, can A have independent columns? rows? Explain
ok rank A means that out of the 4 rows only 2 are non zero when A is in row echelon form. Potentially 3 leading 1s in the columns so at least 2 of the columns may be independent on each other. So independent columns are not possible.
Indepednat rows not possible.
c) Can a non square matrix has its rows indepedant and its columns independent?
im not sure about this. If A (MxN) then for m rows A has n unknowns so it is not possible to have indepdnatn rows. As for the columns i ahve no idea.
If A is m x n and B is n x m show taht AB = 0 iff [itex]col B \subseteq null A[/itex]
suppose AB = 0
let columns of B = [itex]C_{i}[/itex]
rows of A = [itex]R_{i}[/itex]
for all i
then [tex]R_{i} C_{i} = 0 [/itex] if Ci = 0 for all i. Thus Ci belongs to null A<br /> Suppose [tex]col B \subseteq null A[/tex]<br /> then anything times a column of B is zero. Thus AB = 0 <br /> Is this proof adequate?<br /> <br /> your input is greatly appreciated![/tex]