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How is it possible that a n-dimensional spacetime admits m> n INDEPENDENT Killing vectors where m=n(n+1)/2 if the space is maximally symmetric?

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- Thread starter astrolollo
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- #1

- 24

- 2

How is it possible that a n-dimensional spacetime admits m> n INDEPENDENT Killing vectors where m=n(n+1)/2 if the space is maximally symmetric?

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You might want to look at the Killing vectors of Minkowski space as an example. There are 10 of them, so at any given point, some of them are not independent of the others. However, they are independent if you consider them as functions defined on all of space.

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