binbagsss
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Ok I have T_{ij}=μS_{ij} + λ δ_{ij}δS_{kk}.
I am working in R^3.
(I am after S in terms of T) . I multiply by δ_{ij} to attain:
δ_{ij}T_{ij}=δ_{ij}μS_{ij} + δ_{ij} λ δ_{ij}δT_{kk}
=> T_{jj}=δ_{jj}λS_{kk}+μS_{jj} *
My question is , for the LH term of * I choose T_{jj} rathen than T_{ii}. I then get the same decision for μS_{jj} or μS _{ii} on the last term on the RHS. Does this decision need to be consistent with each other?
Next/Main question...
The solution then continues to attain
T_{kk}=(μ+3λ)S_{jj}
Which I can not see how we have got to. δ_{jj}=3, so for RHS of * I get : 3λS_{kk}+μS_{jj} .
I then rename j and k, to get T_{kk} = 3λS_{jj}+μS_{kk}.
My 'S's' do not have the same dummy indice?
Many Thanks to anyone who can shed some light on this !
I am working in R^3.
(I am after S in terms of T) . I multiply by δ_{ij} to attain:
δ_{ij}T_{ij}=δ_{ij}μS_{ij} + δ_{ij} λ δ_{ij}δT_{kk}
=> T_{jj}=δ_{jj}λS_{kk}+μS_{jj} *
My question is , for the LH term of * I choose T_{jj} rathen than T_{ii}. I then get the same decision for μS_{jj} or μS _{ii} on the last term on the RHS. Does this decision need to be consistent with each other?
Next/Main question...
The solution then continues to attain
T_{kk}=(μ+3λ)S_{jj}
Which I can not see how we have got to. δ_{jj}=3, so for RHS of * I get : 3λS_{kk}+μS_{jj} .
I then rename j and k, to get T_{kk} = 3λS_{jj}+μS_{kk}.
My 'S's' do not have the same dummy indice?
Many Thanks to anyone who can shed some light on this !